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程式語言 - LeetCode - C++ - 385. Mini Parser
參考資訊:
https://www.cnblogs.com/grandyang/p/5771434.html
題目:

解答:
/**
* // This is the interface that allows for creating nested lists.
* // You should not implement it, or speculate about its implementation
* class NestedInteger {
* public:
* // Constructor initializes an empty nested list.
* NestedInteger();
*
* // Constructor initializes a single integer.
* NestedInteger(int value);
*
* // Return true if this NestedInteger holds a single integer, rather than a nested list.
* bool isInteger() const;
*
* // Return the single integer that this NestedInteger holds, if it holds a single integer
* // The result is undefined if this NestedInteger holds a nested list
* int getInteger() const;
*
* // Set this NestedInteger to hold a single integer.
* void setInteger(int value);
*
* // Set this NestedInteger to hold a nested list and adds a nested integer to it.
* void add(const NestedInteger &ni);
*
* // Return the nested list that this NestedInteger holds, if it holds a nested list
* // The result is undefined if this NestedInteger holds a single integer
* const vector<NestedInteger> &getList() const;
* };
*/
class Solution {
public:
NestedInteger deserialize(string s) {
if (s[0] != '[') {
return NestedInteger(stoi(s));
}
stack<NestedInteger> st;
int n = s.size();
int num = 0;
bool negative = false;
for (int i = 0; i < n; ++i) {
char c = s[i];
if (c == '[') {
st.push(NestedInteger());
}
else if (c == '-') {
negative = true;
}
else if (isdigit(c)) {
num = (num * 10) + (c - '0');
}
else if (c == ',' || c == ']') {
if (isdigit(s[i - 1])) {
if (negative) {
num = -num;
}
st.top().add(NestedInteger(num));
}
num = 0;
negative = false;
if (c == ']' && st.size() > 1) {
NestedInteger n = st.top();
st.pop();
st.top().add(n);
}
}
}
return st.top();
}
};