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程式語言 - LeetCode - CPP - 264. Ugly Number II
參考資訊:
https://www.cnblogs.com/grandyang/p/4743837.html
題目:

解答:
class Solution {
public:
int nthUglyNumber(int n) {
vector<int> ans(1, 1);
int i2 = 0;
int i3 = 0;
int i5 = 0;
while (ans.size() < n) {
int m2 = ans[i2] * 2;
int m3 = ans[i3] * 3;
int m5 = ans[i5] * 5;
int mn = min({m2, m3, m5});
if (mn == m2) {
i2 += 1;
}
if (mn == m3) {
i3 += 1;
}
if (mn == m5) {
i5 += 1;
}
ans.push_back(mn);
}
return ans.back();
}
};