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程式語言 - LeetCode - CPP - 257. Binary Tree Paths

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題目：


解答：

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
 *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
 *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
 * };
 */
class Solution {
public:
    vector<string> binaryTreePaths(TreeNode* root) {
        vector<string> ans;

        auto dfs = [&](this auto&& dfs, TreeNode *n, string s) {
            if (!n) {
                return;
            }

            if (!s.empty()) {
                s += "->";
            }
            s += to_string(n->val);

            if (!n->left && !n->right) {
                ans.push_back(s);
                return;
            }

            dfs(n->left, s);
            dfs(n->right, s);
        };

        dfs(root, "");
        return ans;
    }
};