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程式語言 - LeetCode - C++ - 2196. Create Binary Tree From Descriptions
題目:

解答:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
TreeNode* createBinaryTree(vector<vector<int>>& descriptions) {
int n = descriptions.size();
unordered_map<int, vector<pair<int, int>>> mp;
for (auto& p : descriptions) {
mp[p[0]].push_back({ p[1], p[2]});
}
int root = -1;
for (auto& p : descriptions) {
bool found = true;
for (auto& c : descriptions) {
if (p[0] == c[1]) {
found = false;
break;
}
}
if (found) {
root = p[0];
break;
}
}
TreeNode* r = new TreeNode(root);
queue<TreeNode*> q;
q.push(r);
while (!q.empty()) {
int size = q.size();
for (int i = 0; i < size; ++i) {
TreeNode* n = q.front();
q.pop();
for (auto& it : mp[n->val]) {
if (it.second) {
n->left = new TreeNode(it.first);
q.push(n->left);
}
else {
n->right = new TreeNode(it.first);
q.push(n->right);
}
}
}
}
return r;
}
};