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程式語言 - LeetCode - C++ - 112. Path Sum

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題目：


解答：

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
 *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
 *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
 * };
 */
class Solution {
public:
    bool hasPathSum(TreeNode* root, int targetSum) {
        if (!root) {
            return false;
        }

        if (!root->left && !root->right) {
            return targetSum == root->val;
        }

        return hasPathSum(root->left, targetSum - root->val) ||
            hasPathSum(root->right, targetSum - root->val);
    }
};